What is the average of the first 9800 natural numbers?

The average of the first 9800 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 9800 natural numbers.

The first 9800 natural numbers are the whole numbers (integers) that start with 1 and end with 9800. To make a list of the first 9800 natural numbers, you simply count up to 9800.

To get the average of those 9800 numbers, you add them up and then divide the sum by 9800. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 9800 in our formula, we get the average of the first 9800 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((9800 × (9800 + 1)) ÷ 2) ÷ 9800
avg = ((9800 × 9801) ÷ 2) ÷ 9800
avg = (96049800 ÷ 2) ÷ 9800
avg = 48024900 ÷ 9800
average = 4900.5

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