What is the average of the first 448 natural numbers?

The average of the first 448 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 448 natural numbers.

The first 448 natural numbers are the whole numbers (integers) that start with 1 and end with 448. To make a list of the first 448 natural numbers, you simply count up to 448.

To get the average of those 448 numbers, you add them up and then divide the sum by 448. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 448 in our formula, we get the average of the first 448 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((448 × (448 + 1)) ÷ 2) ÷ 448
avg = ((448 × 449) ÷ 2) ÷ 448
avg = (201152 ÷ 2) ÷ 448
avg = 100576 ÷ 448
average = 224.5

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