What is the average of the first 262 natural numbers?

The average of the first 262 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 262 natural numbers.

The first 262 natural numbers are the whole numbers (integers) that start with 1 and end with 262. To make a list of the first 262 natural numbers, you simply count up to 262.

To get the average of those 262 numbers, you add them up and then divide the sum by 262. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 262 in our formula, we get the average of the first 262 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((262 × (262 + 1)) ÷ 2) ÷ 262
avg = ((262 × 263) ÷ 2) ÷ 262
avg = (68906 ÷ 2) ÷ 262
avg = 34453 ÷ 262
average = 131.5

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What is the average of the first 263 natural numbers?
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