What is the average of the first 2508 natural numbers?

The average of the first 2508 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 2508 natural numbers.

The first 2508 natural numbers are the whole numbers (integers) that start with 1 and end with 2508. To make a list of the first 2508 natural numbers, you simply count up to 2508.

To get the average of those 2508 numbers, you add them up and then divide the sum by 2508. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 2508 in our formula, we get the average of the first 2508 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((2508 × (2508 + 1)) ÷ 2) ÷ 2508
avg = ((2508 × 2509) ÷ 2) ÷ 2508
avg = (6292572 ÷ 2) ÷ 2508
avg = 3146286 ÷ 2508
average = 1254.5

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