What is the average of the first 2108 natural numbers?

The average of the first 2108 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 2108 natural numbers.

The first 2108 natural numbers are the whole numbers (integers) that start with 1 and end with 2108. To make a list of the first 2108 natural numbers, you simply count up to 2108.

To get the average of those 2108 numbers, you add them up and then divide the sum by 2108. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 2108 in our formula, we get the average of the first 2108 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((2108 × (2108 + 1)) ÷ 2) ÷ 2108
avg = ((2108 × 2109) ÷ 2) ÷ 2108
avg = (4445772 ÷ 2) ÷ 2108
avg = 2222886 ÷ 2108
average = 1054.5

Average of the First Natural Numbers Calculator
Do you need the average of another number of first natural numbers? Please enter your number here.

What is the average of the first 2109 natural numbers?
Here is a similar math problem that we have answered for you.