What is the average of the first 1089 natural numbers?

The average of the first 1089 natural numbers

Here we will define and show you the formula and the math to calculate the average of the first 1089 natural numbers.

The first 1089 natural numbers are the whole numbers (integers) that start with 1 and end with 1089. To make a list of the first 1089 natural numbers, you simply count up to 1089.

To get the average of those 1089 numbers, you add them up and then divide the sum by 1089. We created a formula that can calculate the average of any sequence of natural numbers starting with 1. Here is the formula to calculate the average (avg) of the first n natural numbers:

avg = ((n × (n + 1)) ÷ 2) ÷ n

When we enter n = 1089 in our formula, we get the average of the first 1089 natural numbers. Here is the math and the answer:

avg = ((n × (n + 1)) ÷ 2) ÷ n
avg = ((1089 × (1089 + 1)) ÷ 2) ÷ 1089
avg = ((1089 × 1090) ÷ 2) ÷ 1089
avg = (1187010 ÷ 2) ÷ 1089
avg = 593505 ÷ 1089
average = 545

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